AM/FM Phanto Deluxe phono problem. - EH Scott Radio Enthusiasts2024-03-28T15:47:02Zhttps://ehscott.ning.com/forum/topics/am-fm-phanto-deluxe-phono-problem?commentId=3925821%3AComment%3A128629&feed=yes&xn_auth=noThanks, David. I'll remove ev…tag:ehscott.ning.com,2022-09-22:3925821:Comment:1285532022-09-22T16:07:43.644ZPat Taylorhttps://ehscott.ning.com/profile/PatTaylor
<p>Thanks, David. I'll remove everything else. I have tried a preamp with a 35db gain, and volume is still low. So I've ordered a preamp with a variable gain of up to 60db.</p>
<p>Thanks, David. I'll remove everything else. I have tried a preamp with a 35db gain, and volume is still low. So I've ordered a preamp with a variable gain of up to 60db.</p> My Phantom Deluxe diagram say…tag:ehscott.ning.com,2022-09-22:3925821:Comment:1286292022-09-22T16:00:53.759ZDavid C. Polandhttps://ehscott.ning.com/profile/DavidCPoland
<p>My Phantom Deluxe diagram says a .025 cap between the positive phono terminal and the radio/phono switch, and nothing else. </p>
<p>I used the commonly available 0.022 Mfd film cap.</p>
<p>The Scott input is for a higher output phono cartridge, as Scott was using crystal cartridge pickup, although a magnetic pickup was also available, as per Scott news articles. If your cartridge is good, and is a low output type, then you may need a preamp for the additional audio amp stage.</p>
<p>So, I…</p>
<p>My Phantom Deluxe diagram says a .025 cap between the positive phono terminal and the radio/phono switch, and nothing else. </p>
<p>I used the commonly available 0.022 Mfd film cap.</p>
<p>The Scott input is for a higher output phono cartridge, as Scott was using crystal cartridge pickup, although a magnetic pickup was also available, as per Scott news articles. If your cartridge is good, and is a low output type, then you may need a preamp for the additional audio amp stage.</p>
<p>So, I believe anything else should be removed. And make sure the radio/phono switch is really working. </p>
<p>Maybe someone was attempting to adjust the audio curve with the additional resistor.</p>