Or if in the Zenith world, a "Candohm". In the masterpiece, its 3825; 980; 780; 1975 ohms. Im replacing it with discreet power resistors. 5 or 10 watters?
They wattage can be calculated via Ohm's law and the power formula. However, to shortcut those calculations, if you make each a 5W unit, you should be ok. Making the big one (3825) a 10W unit would be prudent. I never noticed the schematic shows two different resistors with the same voltage drop. If they are, in fact 980 and 780, the drops won't be exactly the same, 980 should be closer to a 30V drop and 780 nearer 20V...in practice, with our higher line voltages, everything will probably be higher, and as long as they are consistent with each other, the set will operate just fine.
230v drop across 7560 ohms gets me close to 6 watts across the array. So 10 watters will be good. Nice catch on that noted 25v drop across two different values!
Factor in a +/- 20 % tolerance and im fine. Thanks for the input.
Randy Rago
Dec 7
Kent King
They wattage can be calculated via Ohm's law and the power formula. However, to shortcut those calculations, if you make each a 5W unit, you should be ok. Making the big one (3825) a 10W unit would be prudent. I never noticed the schematic shows two different resistors with the same voltage drop. If they are, in fact 980 and 780, the drops won't be exactly the same, 980 should be closer to a 30V drop and 780 nearer 20V...in practice, with our higher line voltages, everything will probably be higher, and as long as they are consistent with each other, the set will operate just fine.
Kent
Dec 7
Randy Rago
Factor in a +/- 20 % tolerance and im fine. Thanks for the input.
Dec 7